leetcode-338. 比特位计数

动规思路

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class Solution {
public int[] countBits(int num) {
int[] dp = new int[num + 1];
dp[0] = 0;
if (num == 0) {
return dp;
}
dp[1] = 1;
if (num == 1) {
return dp;
}

for (int i = 2; i <= num; i++){
if (((i-1) & 1) == 1) {
//说明为奇数
String str = Integer.toBinaryString(i - 1);
int index = -1;
int n = str.length();
for (int j = n-1; j >=0; j--) {
if (str.charAt(j) == '0') {
index = j;
break;
}
}
if (index == -1) {
dp[i] = 1;
}else {
dp[i] = dp[i - 1] - (n-index-1) + 1;
}
}else {
dp[i] = dp[i - 1] + 1;
}
}
return dp;
}
}